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Wind representation
Wind representation
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acassata
acassata
posted 2/23/2016 4:05:17 PM
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I found discrepancies between wind numeric value and its representation
The wind vector shows 5 kt less than the numeric value when the speed is divisible by 5 kt.
If it is due to unit conversion and rounded value, e.g. 64 km/h = ~34.56 kt, rounded value = 35 kt, I suggest to round the vector to the closest value instead of rounding down, in the example vector of 35 kt instead of 30 kt.
Moreover, it is possible to show the wind vector for 5 kt with the short line at the second position like the third picture
source:
https://upload.wikimedia.org/wikipedia/commons/c/c6/Wind_barbs.gif
Alexandre
Based at LSGL (Lausanne - La Blécherette, in Switzerland)
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Tim Dawson
Tim Dawson
posted 3/10/2016 5:03:42 PM
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why is it better to show 34.6 with three 10 knot barbs than with three 10 knot barbs + one 5 knot barb?
Because the wind value being shown is less than 35 knots.
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ckurz7000
ckurz7000
posted 3/11/2016 8:46:20 AM
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I guess the barbs represent the closest value (in steps of 5 kts) that is equal to or larger than the actual windspeed. So 51 kts would be represented by a pennant (50 kts) and a half-barb (5 kts) even though just a pennant would be closer to the value. This must be to give the pilot a firm number he can rely on and be sure that the wind will not be stronger than it. There probably is a set definition of how to convert wind speed to barbs. Tim, do you know?
-- Chris.
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3/11/2016 8:47:44 AM by
ckurz7000
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lhe
lhe
posted 3/11/2016 9:05:21 AM
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ckurz7000 (3/11/2016)
I guess the barbs represent the closest value (in steps of 5 kts) that is equal to or larger than the actual windspeed. So 51 kts would be represented by a pennant (50 kts) and a half-barb (5 kts) even though just a pennant would be closer to the value. This must be to give the pilot a firm number he can rely on and be sure that the wind will not be stronger than it. There probably is a set definition of how to convert wind speed to barbs. Tim, do you know?
But that is the opposite of how SD does it.
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lhe
lhe
posted 3/11/2016 9:04:23 AM
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Tim Dawson (3/10/2016)
why is it better to show 34.6 with three 10 knot barbs than with three 10 knot barbs + one 5 knot barb?
Because the wind value being shown is less than 35 knots.
Is there an operational reason why it would be more relevant for the pilot to have the wind speed rounded down to the next lowest multiple of 5 instead of rounded to the closest multiple of 5?
Usually, you would prefer the "nearest" rounding as it would minimise roundoff errors in calculations. The only real exception is when it is important to always round in a "safe" direction, e.g. when checking operating minima.
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Wind representation
acassata
-
2/23/2016 4:05:17 PM
We do not think there is anything wrong with the wind representations...
Tim Dawson
-
2/24/2016 12:50:58 PM
[quote][b]Tim Dawson (2/24/2016)[/b][hr]We do not think there is...
lhe
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3/8/2016 6:39:23 PM
It is exactly my question. In terms of accuracy, I prefer to see 35 kt...
acassata
-
3/10/2016 3:56:16 PM
Is this really such an issue? After all is said and done, what we are...
Sky Painter
-
3/10/2016 5:00:59 PM
[quote]why is it better to show 34.6 with three 10 knot barbs than...
Tim Dawson
-
3/10/2016 5:03:42 PM
I guess the barbs represent the closest value (in steps of 5 kts) that...
ckurz7000
-
3/11/2016 8:46:20 AM
[quote][b]ckurz7000 (3/11/2016)[/b][hr]I guess the barbs represent the...
lhe
-
3/11/2016 9:05:21 AM
[quote][b]Tim Dawson (3/10/2016)[/b][hr][quote]why is it better to...
lhe
-
3/11/2016 9:04:23 AM
There isn't an "operational" reason, it's just my understanding of how...
Tim Dawson
-
3/11/2016 10:58:43 AM
You are right Tim. It's just that rounding down to the nearest 5 kts...
ckurz7000
-
3/12/2016 4:55:21 PM
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